(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A high speed flywheel in a motor is spinning at 450 rpm when a power failure suddenly occurs. The flywheel has mass 35.0 kg and diameter 74.0 cm. The power is off for 33.0 seconds and during this time the flywheel slows due to friction in its axle bearings. During the time the power was off, the flywheel makes 180 complete revolutions.

a. at what rate is the flywheel spinning when the power comes back on.

b. how long after the beginning of the power failure would it have taken the flywheel to stop if the power had not come back on?

c. how many revolutions would the wheel have made during this time?

2. Relevant equations

so i was using the conversions of rev/min to rad/s for part a.

3. The attempt at a solution

i did this:

(180rev/33 sec)*(2*3.14 rad/ 1 rev)=34.3 rad/s

that is not the answer. So, I am guessing there is a bigger formula involved that I am missing.

Please help, thanks in advance.

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# Homework Help: Flywheel slows due to friction in its axle bearings

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