For a string with fixed ends, which normal modes are missing?

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SUMMARY

The discussion centers on identifying missing normal modes for a string with fixed ends, specifically addressing the odd function behavior that leads to the disappearance of even modes. The user confirms that the ends of the string are fixed at ##\xi(0,t) = \xi(L,t) = 0##, which is crucial for applying boundary conditions. The solution involves breaking the equation for a_n into two integrals and enforcing matching conditions at the midpoint, ##\xi(L/2,t)##.

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snickersnee
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Homework Statement



Here's the problem. I was able to find the a_n and b_n values, my question is mainly on part (c), how do I find which modes are missing? The function is odd, so even modes should disappear, but cos(n*pi) doesn't disappear, it's either +1 or -1. I'd greatly appreciate any help.

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Homework Equations



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b_n = 0 because released from rest[/B]

The Attempt at a Solution



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When it says fixed ends, are we to assume that at x = 0 and x = L, the ends are fixed at ##\xi(0,t) = \xi(L,t) = 0##?
If so, then you should be able to say something about ##\xi( L/2,t)##.

Using your equation for a_n, break that into two integrals, one from 0 to L/2 and one from L/2 to L. Then enforce an appropriate matching condition for ##\xi(L/2,t) ## and ##\xi_t(L/2,t)##
 

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