Force alongside the inside of a hemispherical bowl

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SUMMARY

The discussion focuses on calculating the total force exerted alongside the inside of a hemispherical bowl filled with milk, with a diameter of 16 cm and a density of 1050 kg/m³. The participant correctly identifies the force on the bottom of the bowl using the formula: Density * Gravitational Constant * Volume = 1050 * 9.8 * π * 8². For the sides, they propose using integration to compute the force by considering the bowl from a top-down perspective, applying the integral: ∫(from 0 to 8) 2πh * √(64-h²) * 1050 * 9.8 dh. The participant expresses uncertainty about the method but believes it is logically sound.

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Homework Statement


There is a bowl filled with milk with a diameter of 16cm. (The density of milk is 1050 kg/m³). Find the total force alongside the inside of the bowl.


Homework Equations





The Attempt at a Solution



I decided to break this problem up. First of all, its the first time we've dealt with a hemisphere, so I wasn't too sure on how to approach it, but this is what I came up with:

Force on the bottom of the bowl (a constant): Bottom: Density * Gravitational Constant * Volume = 1050*9.8*pi*8².

Now, to find the force on the sides using integration. I decided to take a look at the bowl from a top down perspective, doing so, I get a circle. Now, I can apply integrals to calculate every 'ring' from the inside to the outside of the bowl.

(integral from 0 to 8)
[tex]\int[/tex]2*pi*h * sqrt(64-h²) * 1050 *9.8 dh

I am very unsure if this method would work, but logically...it seems alright with me!
 
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I had a quick look and I would do exactly the same thing :smile:
 
3029298 said:
I had a quick look and I would do exactly the same thing :smile:

Thanks, are you sure that the force on the bottom is the right constant? going to the help center, someone said there wouldn't be any force, I just couldn't believe him.
 

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