Force applied at an angle to a box?

  • Thread starter Affie
  • Start date
  • #1
Affie
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Homework Statement


A net force of 4N to the right is applied to a box of 6kg while moving it a distance of 3m to the right.
(1)How much work is done on the box?
(2)What if the force is applied at a 30 degree angle above horizontal?


Homework Equations


(1) W=Fdcos(angle)
(2) F=ma
(3) W=Kf-Ki=((1/2)mv^2)-((1/2)mv^2)

The Attempt at a Solution


For the first question, to find the work done on the box, I plugged numbers into equation (1).
W=(4N)(3m)cos(0)
Cos(0)=1, W=12J

I don't even know where to begin for question (2). It seems to me that, in order to caclulate Force, I need the acceleration to plug into equation 2, or I need velocities to calculate work in equation (3). I have neither, and I can't think of any other applicable equations. I assumed friction was negligable since it was not mentioned.
 

Answers and Replies

  • #2
willem2
2,089
348
why wouldn't plugging numbers in equation 2 work here as well? You already have the force.
 
  • #3
Affie
2
0
Okay, I feel crazy. I got work and force mixed up and what the questions were asking mixed up. I feel dumb.

So, equation (1) is used for both questions. The force is the same, the distance is the same, the only thing that changes is the angle.

Thanks.
 

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