Force applied to block moving along table

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SUMMARY

The discussion focuses on the dynamics of an object subjected to a time-dependent force, specifically Fx = c1t, where c1 is a constant. The problem involves calculating the object's velocity as it moves along a horizontal table, ignoring friction. The textbook solution provided is v = (c1/2m * (6mA/c1)^(2/3)). Participants emphasize the need to relate time (t) to the distance (A) to derive the correct velocity equation, suggesting the use of calculus for this transformation.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with basic calculus concepts
  • Knowledge of kinetic energy and potential energy equations
  • Concept of force and friction in physics
NEXT STEPS
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  • Learn how to apply calculus to derive relationships in physics problems
  • Explore the concept of work-energy theorem in mechanics
  • Investigate the effects of friction on motion and energy conservation
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Homework Statement



An object of mass is placed at rest at the point x=0 on a horizontal table and at time t=0, a horizontal force is applied to it given by Fx = c1t where c1 is a known positive constant. The coefficient of friction between the table and the object is u.

If friction force is ignored what will be the object's velocity in the direction when it reaches point A (point A is right of x = 0)

Homework Equations



conservation of energy
kinetic energy1 + potential erngery1 = kinetic energy2 + potential energy 2

textbook answer: c1/2m * (6mA/c1)^2/3

The Attempt at a Solution


using above formula
0 + 0 = 1/2mv2 - c1t2/2

c1t = ma
t = ma/c1 (plug into above equation)

v = (ma2/c1)1/2
 
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Inserting 'a' doesn't get you far because it is another variable that does not appear in the required answer. Instead of replacing t with a, you need to replace it with A. Can you get an equation relating t to A? (Might need some calculus - is that OK?)
 

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