What's the least force we should apply?

  • Thread starter Thread starter PhysicS FAN
  • Start date Start date
  • Tags Tags
    Apply Force
Click For Summary

Homework Help Overview

The problem involves two objects of equal mass connected by a thread on a frictionless surface, with a focus on determining the minimum force required to break the thread, which has a tension limit of 20N.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the forces acting on the system, including the applied force and tension in the thread. There is an exploration of the relationship between force, tension, and acceleration, as well as the implications of breaking the thread.

Discussion Status

The discussion has seen participants questioning the initial setup and assumptions regarding the forces involved. Some guidance has been provided through questions that prompted deeper thinking about the dynamics of the system, leading to a clearer understanding of the relationships between the forces.

Contextual Notes

Participants are navigating the complexities of a system with two objects and the implications of applying force, including the effects of acceleration and the conditions under which the thread will break.

PhysicS FAN
Messages
26
Reaction score
4

Homework Statement


2 objects of the same mass are on a non-frictional level and are connected with a thread which has a resistibility limit T=20N. What is the least froce we should apply so that the thread breaks?

Homework Equations

The Attempt at a Solution


I don't know how to proceed with this problem since the system contains of 2 objects. My first thought was to use kinetic energy theorem on the first body since Kτελ-Καρχ=0 and then find a relationship with the tension of the thread and the force based on the energy theorems but that didnt work. Please help me
 

Attachments

  • 52470683_2512809535427327_6650656497355194368_n.jpg
    52470683_2512809535427327_6650656497355194368_n.jpg
    13.5 KB · Views: 351
Physics news on Phys.org
You need to think about all the forces on your system.
 
  • Like
Likes   Reactions: PhysicS FAN
PeroK said:
You need to think about all the forces on your system.
Yes there's the force that we apply and the tension.
 
PhysicS FAN said:
Yes there's the force that we apply and the tension.

What happens when you apply a force?
 
  • Like
Likes   Reactions: PhysicS FAN
PeroK said:
What happens when you apply a force?
Well in this case the force will accelerate the system which may or may not had an initial velocity. If the force is big enough it will break the thread. Now after the thread breaks the left object will continue moving with the speed it had just before the moment that the break of the yarn happened because there is no friction and accroding to Newtons 1st Law it will continue moving. In the left object the force that is causing the acceleration is the tension of the thread so T=m*a . In the second object the tension is in the opossite direction of the force so: F-T=m*a. Now if we solve for F we get F=m*a+T . But from the first equation we know that m*a= T and so the force is equal to F=2T=2*20=40N.
I don't know what you did but you helped me solve the problem with only a question. Thank you!:smile::smile:
 
  • Like
Likes   Reactions: Delta2 and PeroK

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
4K
Replies
29
Views
3K
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 58 ·
2
Replies
58
Views
3K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K