Force between two perpendicular wires

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SUMMARY

The discussion focuses on calculating the force between two perpendicular wires using the formula for the magnetic field, B=μ0i/(2πr). A participant identifies a sign error in the force calculation, specifically regarding the direction of the force vector dF in relation to the magnetic field B and the differential length vector dl. The correct expression for the force is dF=Idl × B, emphasizing the need for a unit vector to indicate direction. Participants confirm that the magnitude of the force calculation is correct, but caution is advised in ensuring the correct application of vector quantities.

PREREQUISITES
  • Understanding of vector calculus and cross products
  • Familiarity with magnetic fields and forces in electromagnetism
  • Knowledge of the Biot-Savart Law and its applications
  • Experience with unit vectors and their significance in vector quantities
NEXT STEPS
  • Study the Biot-Savart Law for magnetic field calculations
  • Learn about vector cross products and their applications in physics
  • Explore the concept of magnetic force on current-carrying conductors
  • Investigate the role of unit vectors in vector mathematics
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Physics students, electrical engineers, and anyone studying electromagnetism, particularly those interested in the interactions between current-carrying wires.

Eitan Levy
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Homework Statement
In a system as described in the picture, what would be the force that the infinite wire with a current of i exerts on the wire BC?
Relevant Equations
F=BILsinΘ
μThe magnetic field is supposed to be B=μ0i/(2πr). I think that the force would be aimed upwards.

Now I tried to divide the wire BC to infinite smaller wires where B is roughly constant in each one of them.

What I get is:
Capture.PNG

However this is not correct when I plug the relevant numbers in it.

Where is my mistake?
 

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Your work looks basically correct.

1576026551371.png

I think there's a sign error on the right-hand side. Is the force ##\vec{dF}## in the same direction as ##\vec B \times \vec{dl}##? I assume that you are using the usual convention that ##\vec{dl}## is in the same direcrion as the current in ##dl##.

1576026769378.png

The left side is a vector quantity while the right side is a scalar quantity. So, you should include a unit vector on the right side to indicate the direction of the quantity on the left side.

Your final result looks correct for the magnitude of the force on BC. Were you also expected to give the direction of the force?
 
How do you know that you plugged in the numbers correctly? Show us the numbers and exactly what you did. Also, the force is ##d\vec F=Id\vec l \times \vec B##. You show the negative of this.
 
I indeed plugged the numbers wrong. Thanks for the heads up about the wrong direction of dF, I will be more careful.
 
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