Force Diagrams for a Combined Mass

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SUMMARY

The discussion centers on the forces acting on a truck, specifically the relationship between the engine's driving force and the opposing forces of friction and the force exerted by the trailer (F_{BonA}). Participants clarify that while the engine provides angular acceleration to the wheels, the actual force propelling the truck forward is the friction between the wheels and the ground. The driving force must exceed the combined forces of friction and the trailer's resistance (F_{BonA} and F_k) for the truck to accelerate. The conversation emphasizes the importance of accurately defining forces in free body diagrams (FBD).

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams (FBD)
  • Knowledge of frictional forces and their role in motion
  • Concept of net force and its calculation (NET force = mass x acceleration)
NEXT STEPS
  • Research the role of friction in vehicle dynamics
  • Study the principles of free body diagrams in physics
  • Explore the relationship between angular acceleration and translational motion
  • Learn about the effects of trailers on vehicle acceleration and dynamics
USEFUL FOR

Physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicles and the forces acting upon them.

rmiller70015
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Homework Statement
A truck that is towing a trailer is accelerating, draw the force diagram for the truck and the trailer
Relevant Equations
F = ma
I know that the ##F_{AonB} = -F_{BonA}##, but I just wanted to check something. If object A is the truck, then the x-direction should have a vector coming from the force of the engine driving the truck forward, a vector pointing in the negative direction for friction, and a vector in the negative direction for ##F_{BonA}##. But for the FBD of the truck, does the driving force vector need to be larger than the combined ##F_{BonA}## and ##F_k## or just larger than the friction force?
 
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rmiller70015 said:
a vector coming from the force of the engine driving the truck forward, a vector pointing in the negative direction for friction,
What is this force the engine exerts on the truck? Isn't the engine part of the truck?
And what friction force do you have in mind opposing that? Try to be precise.
rmiller70015 said:
for the FBD of the truck, does the driving force vector need to be larger than the combined ##F_{BonA}## and ##F_k## or just larger than the friction force?
Would the truck go faster without the trailer?
Remember, NET force = mass x acceleration.
 
haruspex said:
What is this force the engine exerts on the truck? Isn't the engine part of the truck?
This is used in many introductory books in physics, that is that they resemble the role of the engine as something that supplies an external force to the vehicle. Of course what happens in reality is that the engine provides angular acceleration to rotate the wheels and the real external force that gives translational acceleration to the vehicle is the friction between the rotating wheels and the ground.
 
Delta2 said:
This is used in many introductory books in physics, that is that they resemble the role of the engine as something that supplies an external force to the vehicle. Of course what happens in reality is that the engine provides angular acceleration to rotate the wheels and the real external force that gives translational acceleration to the vehicle is the friction between the rotating wheels and the ground.
Contrast that with what post #1 says about friction.
 
haruspex said:
Contrast that with what post #1 says about friction.
So you trying to say that friction is an accelerating force, not a decelerating one?
 
Delta2 said:
So you trying to say that friction is an accelerating force, not a decelerating one?
It depends what the OP meant by friction in post #1, hence the question in post #2..
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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