Force due rotation about axis parallel to centroidal axis

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When analyzing a disc rotating about an axis parallel to the centroidal axis with unbalanced mass, the initial formula F = m x r x w^2 needs adjustment. It is important to recognize that the term "force" in this context is actually a product of mass and acceleration. To find the force of unbalancing in the new geometry, one should apply similar principles as in the original case. By recalculating based on the new axis, the same fundamental relationships will apply. This approach ensures accurate determination of the forces involved in the rotation.
mohammed othman
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in the case of a disc rotating about the centroidal axis and having an unbalanced mass we used the formula
F(force)=m x r x w^2, where r is the distance from the center to the center, m mass of the unbalanced, w rotational speed
in the case of a disc rotating about axis parallel to the centroidal axis what equation we may use, what equation shall we use to obtain the force of unbalancing.
 
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Start by recognizing that the "force" you used in the first place was not a force at all but a mass x acceleration term. For the new case, do the same thing in the new geometry; it will work out.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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