# Force Exerted by Blocks on a Frictionless Surface

• farrah003
In summary, three blocks of mass 5, 10, and 25 kg are lined up on a frictionless surface with a force of 14 N applied to the left-most block. The magnitude of the force that the middle block exerts on the rightmost one is 8.75 N and the magnitude of the force that the leftmost block exerts on the middle one is 7/15 N. When the order of the blocks is reversed, the magnitude of the force that the leftmost block exerts on the middle one is still 7/15 N.
farrah003
1. Homework Statement

Blocks of mass 5, 10, and 25 kg are lined up from left to right in that order on a frictionless surface so each block is touching the next one. A rightward-pointing force of magnitude 14 N is applied to the left-most block.

a) What is the magnitude of the force that the middle block exerts on the rightmost one?
Fright, middle = 8.749999995
b) What is the magnitude of the force that the leftmost block exerts on the middle one?
Fmiddle, left = ?
c) Suppose now that the left-right order of the blocks is reversed. Now find the magnitude of the force that the leftmost block exerts on the middle one?
F'middle, left = ?

i figured out the first part i just need help to do the last two

I don't think (a) is right. Here's what I would do.

F = ma

The force pushing on the blocks is equal to their total mass times their acceleration but we have to solve for acceleration.

14 = 30a

a = 7/15

Use F = ma for every question and don't forget Newton's 3rd law

part a is correct because the homework is on a software and it accepted my answer

how did you get a

Nevermind. I screwed up. The total mass of the blocks is equal to 40 not 30. So a is right.

## 1. What is the force exerted by a block on a frictionless surface?

The force exerted by a block on a frictionless surface is known as the normal force. It is equal in magnitude but opposite in direction to the force of gravity acting on the block.

## 2. How is the force exerted by a block on a frictionless surface calculated?

The force exerted by a block on a frictionless surface can be calculated using the formula F = m * g, where F is the force, m is the mass of the block, and g is the acceleration due to gravity.

## 3. Does the weight of the block affect the force exerted on a frictionless surface?

No, the weight of the block does not affect the force exerted on a frictionless surface. The force is solely determined by the mass of the block and the acceleration due to gravity.

## 4. What happens to the force exerted by a block on a frictionless surface when the mass of the block changes?

The force exerted by a block on a frictionless surface will change proportionally to the change in mass. If the mass increases, the force will increase, and if the mass decreases, the force will decrease.

## 5. Can the force exerted by a block on a frictionless surface be negative?

No, the force exerted by a block on a frictionless surface cannot be negative. Since the force is equal in magnitude but opposite in direction to the force of gravity, it will always be a positive value.

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