The discussion revolves around the pressure relationship in a fluid flowing through a bent pipe, specifically questioning why the pressures at two points, P1 and P2, are considered equal despite an elevation difference between the inlet and outlet. The subject area pertains to fluid mechanics.
There is an ongoing exploration of the assumptions regarding elevation differences and atmospheric pressure. Some participants have provided insights into why certain factors may be neglected, while others seek further clarification on these points. Multiple interpretations of the problem are being discussed.
Participants note that the problem does not provide specific inlet and outlet elevations, which may influence the analysis. There is also mention of the problem's assumptions regarding the fluid's velocity and thickness.
The author is right. There is atmospheric pressure at inlet and outlet.foo9008 said:Homework Statement
refer to part 8.2 in this problem , why P1 = P2 ?
http://www.efm.leeds.ac.uk/CIVE/CIVE1400/Examples/eg6_ans.htmThe Attempt at a Solution
there's some elevation between inlet and outlet , how can P1 = P2 , is the author wrong ? [/B]
Chestermiller said:The author is right. There is atmospheric pressure at inlet and outlet.
In their analysis, they are also neglecting the elevation difference between inlet and outlet and also the weight of the fluid.
why the elevation difference between inlet and outlet can be neglected ?Chestermiller said:The author is right. There is atmospheric pressure at inlet and outlet.
In their analysis, they are also neglecting the elevation difference between inlet and outlet and also the weight of the fluid.
P1 and P2 are not atmospheric pressure as shown in the calculation , why P1 = P2?Chestermiller said:The author is right. There is atmospheric pressure at inlet and outlet.
In their analysis, they are also neglecting the elevation difference between inlet and outlet and also the weight of the fluid.
Because the static pressure difference between the inlet and outlet elevations is small compared to the pressure exerted on the surface of the blade, and the weight of the fluid in the control volume is small compared to force exerted by the blade to change the direction of the fluid jet.foo9008 said:why the elevation difference between inlet and outlet can be neglected ?
Look at the figure. P1 and P2 are both atmospheric. This isn't an enclosed tube. It's a jet open to the atmosphere.foo9008 said:P1 and P2 are not atmospheric pressure as shown in the calculation , why P1 = P2?
this is the(hand-written) question that i wish to ask , but then , i found the somewhat the same typed question on the internet , so i copy the link and ask here . ok , it's much clearer now .Chestermiller said:Because the static pressure difference between the inlet and outlet elevations is small compared to the pressure exerted on the surface of the blade, and the weight of the fluid in the control volume is small compared to force exerted by the blade to change the direction of the fluid jet.
We can calculate each of them and compare their magnitudes. The problem statement also inherently implies that you can neglect the elevation change, since it doesn't even give you the inlet and outlet elevations, and it assumes that the velocity and thickness of the jet doesn't change: "75mm wide and 25mm thick, strike the vane with a velocity of 25m/s."foo9008 said:this is the(hand-written) question that i wish to ask , but then , i found the somewhat the same typed question on the internet , so i copy the link and ask here . ok , it's much clearer now .
how do we know that the static pressure difference between the inlet and outlet elevations is small compared to the pressure exerted on the surface of the blade?