Can anyone tell me how to determine the force necessary to spin an alternator at the rated RPM?
No, because that depends upon properties of the specific alternator. In particular, the friction in the alternator itself and the time in which it is brought up to that RPM.
....and the electrical load on the alternator.
ok hypotheically then, let's say it's a 6000 watt generator head taken from a portable home backup generator. if i have 6400lbs-ft of constant force and the generator head operates at either 3600 rpm or 1800 rpm...without knowing the specific details such as mass(approx. 60-80lbs of rotational parts) or friction, is it possible to determine the force necessary? also does anyone know of a website that offers detailed information on alternators and/or suppliers that I could purchase one from?
about 5 horsepower for 100 amp alternator
Torque (Newton-meters) in angular rotation is the equivalent to force (Newtons) in linear motion. For an alternator, the power output (watts) is the product of the angular force times the angular speed. Specifically
T x 2 pi RPM/60 = W watts, where the torque T is in Newton-meters.
So for a 6000 watt alternator output (at 100% efficiency) at 3600 RPM, the torque is
T = 60 W/ 2 pi RPM = 15.9 Newton-meters.
6000 watts (at 100% efficiency) is equal to 8.04 HP
be advised that in the real world alternators are 40% efficient which is why there is a difference between calculated HP and actual parasitic HP required to turn the Alt.
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