Force necessary to support mass on Hydraulic Jack?

Click For Summary

Homework Help Overview

The discussion revolves around determining the force necessary to support a mass using a hydraulic jack, specifically involving two pistons with different diameters and a given mass. The problem is situated within the context of fluid mechanics and hydraulic systems.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between forces and areas of the pistons, referencing the equation F1*A1 = F2*A2. There are attempts to calculate the required force using given dimensions and mass, with some participants questioning the correctness of their calculations and the equations used.

Discussion Status

Several participants have provided insights and clarifications regarding the equations involved. There is ongoing exploration of the calculations, with one participant indicating they have resolved their issue, although the specifics of that resolution are not detailed.

Contextual Notes

Participants note the assumption of neglecting height differences between the pistons and the massless nature of the pistons, which are critical to the problem setup. There is also a request for a visual aid to better understand the problem context.

jumpingjack90
Messages
14
Reaction score
0
Force necessary to support mass on Hydraulic Jack?

Homework Statement


Piston 1 in the figure has a diameter of 1.31 cm. distance of 2 in
Piston 2 has a diameter of 7.91 cm. distance of 10 in
In the absence of friction, determine the force F, necessary to support an object with a mass of 904 kg placed on piston 2. (Neglect the height difference between the bottom of the two pistons, and assume that the pistons are massless).

Homework Equations


F1*d1 = Fp*d2, where d1 is the moment arm of F1, and d2 is
the moment arm of Fp.

The Attempt at a Solution


Fp = (F1*d1)/d2
(904)(9.81)/(pi)(0.003955)^2= F/(pi)(0.00655)^2
F=242.98 N which was incorrect.
anyone have an idea of what I should do and what equation to use? Thanks!
 
Physics news on Phys.org


I think we'll need to see the figure before we can help you out.
 


http://img6.imageshack.us/img6/7849/1808317ca439856447261f7.gif

this is the link for the picture.
 
Last edited by a moderator:


Neglecting the height difference means the pressure should be the same, thus F_1 A_1 = F_2 A_2

This is would be the force exerted on the small piston.

You should know how to find the force needed by the hand from this.
 


jumpingjack90 said:

Homework Equations


F1*d1 = Fp*d2, where d1 is the moment arm of F1, and d2 is
the moment arm of Fp.

The Attempt at a Solution


Fp = (F1*d1)/d2
(904)(9.81)/(pi)(0.003955)^2= F/(pi)(0.00655)^2
F=242.98 N which was incorrect.
anyone have an idea of what I should do and what equation to use? Thanks!

You have correctly found F1, the force on the smaller piston. However, they are asking for Fp (labelled simply F in the figure), the force exerted by the hand.

You have the equation to find Fp given F1.
 


ok. I used the equation given and solved for Fp. I had (242.98)(pi*(0.03955)^2))/(pi)*(0.00655)^2=Fp=8858.92 N, which is also incorrect.
what am I doing wrong?
 


nvm. I solved it! thanks everyone for your input!
 


jumpingjack90 said:
nvm. I solved it! thanks everyone for your input!

how u solved it my friend?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K