Force needed to pull out a plug out of a drain under water?

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SUMMARY

The force required to remove a circular plug from a drain located 3.0 meters below the surface of water is calculated to be 57.624 N. This calculation uses the formula F = P * A, where P is the hydrostatic pressure and A is the area of the plug. The area is determined using A = π * r², with a radius of 0.025 m. Atmospheric pressure does not affect the force calculation since it cancels out in this scenario.

PREREQUISITES
  • Understanding of hydrostatic pressure principles
  • Familiarity with the formula for area of a circle (A = π * r²)
  • Knowledge of basic physics equations related to force (F = P * A)
  • Concept of pressure differences in fluid mechanics
NEXT STEPS
  • Study hydrostatic pressure calculations in fluid mechanics
  • Learn about the effects of atmospheric pressure on submerged objects
  • Explore applications of Pascal's principle in real-world scenarios
  • Investigate the impact of fluid density on force calculations
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Students studying physics, particularly those focusing on fluid mechanics, as well as engineers involved in hydraulic systems and pressure calculations.

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Homework Statement


The plug for the drain of a water tower is located 3.0 m below the surface. The plug is circular and has a diameter of 5.0 cm. If the density of water is 1000 kg/m3 , how much force is required to remove the plug (you may ignore the weight of the plug itself)

Homework Equations


A= pi * r ^2
F=P *A

The Attempt at a Solution


A = pi * r^2 = pi * (0.025)^2 =1.96 * 10 ^-3 m^2

F= pGH * A
= (1000 kg/m3) (9.8) (3.0 m) * 1.96 * 10 ^-3 m^2
= 57.624 N

is this correct? there is no pressure from the atmosphere right?
 
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qwertyqwert321 said:

Homework Statement


The plug for the drain of a water tower is located 3.0 m below the surface. The plug is circular and has a diameter of 5.0 cm. If the density of water is 1000 kg/m3 , how much force is required to remove the plug (you may ignore the weight of the plug itself)

Homework Equations


A= pi * r ^2
F=P *A

The Attempt at a Solution


A = pi * r^2 = pi * (0.025)^2 =1.96 * 10 ^-3 m^2

F= pGH * A
= (1000 kg/m3) (9.8) (3.0 m) * 1.96 * 10 ^-3 m^2
= 57.624 N

is this correct? there is no pressure from the atmosphere right?
The atmospheric pressure is in addition to the 58N to give the total pressure from above. The pressure from below is just atmospheric. So the atmospheric pressure cancels.
 

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