Force Needed to Push 30 Tonne Rubbish in Steel Container

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SUMMARY

The force required to push 30 tonnes of rubbish from a smooth steel container is estimated to be approximately 150 kN, based on a coefficient of friction ranging from 0.4 to 0.6 for timber on steel. This calculation assumes a perfectly horizontal push without any obstructions or surface irregularities. Factors such as moisture, rust, and the surface to which the rubbish is being pushed can significantly affect the actual force needed.

PREREQUISITES
  • Understanding of friction coefficients, specifically timber on steel
  • Basic knowledge of force calculations in physics
  • Familiarity with the concept of weight and mass in tonnes
  • Awareness of factors affecting friction, such as surface conditions
NEXT STEPS
  • Research the effects of surface conditions on friction coefficients
  • Learn about the physics of force calculations in horizontal motion
  • Explore methods to reduce friction in heavy load applications
  • Investigate the impact of different materials on friction with steel surfaces
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Engineers, physicists, and logistics professionals involved in material handling and load movement optimization will benefit from this discussion.

dpac
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Hello members,

Can anyone help me with the following.

How much force is required to push 30 tonne of rubbish from a enclosed smooth steel container, sitting level with the ground?

Rubbish contents (timber, plastic, dirt, food, etc)

I was under the impression that the coefficient of friction of say timber on steel is 0.4-0.6. Therefore to push 30t of this material should take roughly 150kn.

Thanks for any help.

Dave
 
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That is certainly a reasonable estimate, if you push perfectly horizontal, if nothing else is blocking (sides of the container, uneven surface, rusted together, ...), everything is dry, the surface you want the rubbish to be afterwards is also steel (or similar to it) and no other issues occur.
 

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