- #1
Spartan301
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Hi, I'm new here and I hope I'm posting in the right place. I have a question regarding Newton's Law of Gravitation, and it involves the formula:
F = GMm/r^2
You know, where F = Force of Gravity, G = 6.67e-11N*m^2, then M and m are two masses, and then r is the distance between the two masses squared.
The key is telling me I have the wrong answer. The correct answer is (2.0e-9,-5.2e-10) N.
Here's the question and my work:
Three 8.00 kg spheres are located on three corners of a square. Mass A is at (0, 1.7) meters, mass B is at (1.7, 1.7) meters, and mass C is at (1.7, 0) meters. Calculate the net gravitational force on A due to the other two spheres. Give the components of the force.
Mass; 8.00 kg
Mass A Located: (0,1.7)meters
Mass B Located: (1.7,1.7)meters
Mass C Located: (1.7,0) meters
Objective: Find net gravitational force on A due to the other two spheres. Give the components of the force.
Battle Plan:
Triangulate distance between A and B
Find Force of Gravity using Newton’s Law
Triangulate distance between A and C
Find Force of Gravity using Newton’s Law
Action Report and Outcome:
Distance between A and B is 1.7 m.
F = GMm/r^2
F = [(6.67e-11 N*M^2/kg^2)(8.00 kg)(8.00 kg)]/(1.7m)^2
F = (426.88e-11 N*m^2)/(2.89m^2)
F = 147.7093426e-11 N
Sig figs: 2
1.5e-9 N
(1.48e-9 N, 1.7m)
Distance between A and C: (0,1.7),(1.7,0)
D = sqrt(x2-x1)^2+(y2-y1)^2
D = sqrt(1.7-0)^2+(0-1.7)^2
D = sqrt(1.7)^2+(-1.7)^2
D = sqrt(2.89)+(2.89)
D = sqrt(5.78)
D = 2.404163056 m
sig figs: 2
D = 2.4 m
F = GMm/r^2
F = [(6.67e-11 N*M^2/kg^2)(8.00 kg)(8.00 kg)]/(2.404163056m)^2
F = (426.88e-11 N*m^2)/5.78m^2
F = 73.85467128e-11 N
F = 7.39e-10 N
I'd really appreciate help, and let me know if I can return the favor.
-Tom
F = GMm/r^2
You know, where F = Force of Gravity, G = 6.67e-11N*m^2, then M and m are two masses, and then r is the distance between the two masses squared.
The key is telling me I have the wrong answer. The correct answer is (2.0e-9,-5.2e-10) N.
Here's the question and my work:
Three 8.00 kg spheres are located on three corners of a square. Mass A is at (0, 1.7) meters, mass B is at (1.7, 1.7) meters, and mass C is at (1.7, 0) meters. Calculate the net gravitational force on A due to the other two spheres. Give the components of the force.
Mass; 8.00 kg
Mass A Located: (0,1.7)meters
Mass B Located: (1.7,1.7)meters
Mass C Located: (1.7,0) meters
Objective: Find net gravitational force on A due to the other two spheres. Give the components of the force.
Battle Plan:
Triangulate distance between A and B
Find Force of Gravity using Newton’s Law
Triangulate distance between A and C
Find Force of Gravity using Newton’s Law
Action Report and Outcome:
Distance between A and B is 1.7 m.
F = GMm/r^2
F = [(6.67e-11 N*M^2/kg^2)(8.00 kg)(8.00 kg)]/(1.7m)^2
F = (426.88e-11 N*m^2)/(2.89m^2)
F = 147.7093426e-11 N
Sig figs: 2
1.5e-9 N
(1.48e-9 N, 1.7m)
Distance between A and C: (0,1.7),(1.7,0)
D = sqrt(x2-x1)^2+(y2-y1)^2
D = sqrt(1.7-0)^2+(0-1.7)^2
D = sqrt(1.7)^2+(-1.7)^2
D = sqrt(2.89)+(2.89)
D = sqrt(5.78)
D = 2.404163056 m
sig figs: 2
D = 2.4 m
F = GMm/r^2
F = [(6.67e-11 N*M^2/kg^2)(8.00 kg)(8.00 kg)]/(2.404163056m)^2
F = (426.88e-11 N*m^2)/5.78m^2
F = 73.85467128e-11 N
F = 7.39e-10 N
I'd really appreciate help, and let me know if I can return the favor.
-Tom