Force of one wire due to the other

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Homework Help Overview

The discussion revolves around the calculation of the force exerted on one wire due to the magnetic field generated by another wire carrying current. The context involves concepts from electromagnetism, specifically the interaction between current-carrying wires and magnetic fields.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the magnetic field produced by a wire and its relation to the force on another wire. Questions arise regarding the application of relevant equations and the interpretation of variables such as the length of the wire.

Discussion Status

Participants are actively exploring the relationship between the magnetic field and the force on the wire, with some providing guidance on the equations to use. There is an ongoing examination of the variables involved, particularly the length of the wire and the direction of the force.

Contextual Notes

There is a mention of the need to determine the force per unit length and the implications of the wire's orientation relative to the magnetic field. Some participants express uncertainty about the units of measurement involved in the calculations.

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Homework Statement



3.jpg


D=1.0cm=0.01m
I=1.0A


Homework Equations


B=(μ0I)/(2∏r)

The Attempt at a Solution



B1=(4∏x10^-7 * 1.0A)/(2∏ * 0.01m)= 2.0x10^-5

B2=(4∏x10^-7 * 1.0A)/(2∏ * 0.01m)= 2.0x10^-5

Not sure what to do with these two numbers.
 
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How does the force on a wire relate to the current through the wire and the B field?
 
I would use the Right Hand Rule to find the relation. Since the current is going upward (thumb), the magnetic field B would be going into the page (fingers) and the force would be pointing to the left (direction the palm faces).
 
The right hand rule will give the direction of the force but not the magnitude. You have found B, the magnetic field produced by a wire carying 1 amp at a distance of 10 cm. Now How do you find the magnitude of the force on the wire that is in this field?
 
Would I use F=|q0|vBsinθ ?
 
Wait, nevermind. That would be for a moving particle.
 
F = BIL, remember this?
 
F=ILBsinθ would be the equation, I think.
 
Oh, saw your post after I posted. Oops. What would be L? I thought that L was the length of the wire, but that was not a given variable.
 
  • #10
If you have studied Vectors i would suggest you use the more general equation force that is i*L(cross)B
 
  • #11
F=ILBsinθ is technically correct and is used if the wire is not perpendicular to the B field which it is in this case. s far as what is L, look it up in your text. It will do you some good :-) Remember the force requested is per unit length.
 
  • #12
Oh ok, so...

F/L=(1.0A)(2x10^-5)

and sin90=1

So F/L=2*10^-5
 
  • #13
would the units be Gauss/meter?
 
  • #14
What is the unit of force?
 
  • #15
oops, N/m!
 
  • #16
Remember that this is a two step process. Step 1 is to determine the B
field in the vicinity of the wire, and step 2 is to determine the force on the wire due to the B field generated by the other wire..
 

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