1. The problem statement, all variables and given/known data Two people, each with a mass of 70 kg, are wearing inline skates and are holding opposite ends of a 15 m rope. One person pulls forward on the rope by moving hand over hand and gradually reeling in more of the rope. In doing so, he exerts a force of 35 N [backwards] on the rope. This causes him to accelerate toward the other person. Assuming that the friction acting on the skaters is negligible, how long will it take for them to meet? Explain your reasoning. T/I 2. Relevant equations F = ma 3. The attempt at a solution 35N / 70 kg = 0.5 m/s/s displacement = 0.5*a*t^2 7.5 = 0.25 * t^2 Since they are both accelerating towards each other because of newton's third law, only half the distance is required to be traveled, so it takes 5.47 seconds for them to meet. The answer at the answer key of my book says that it takes 7.7 seconds, they have used 15m in the equation instead of 7.5. If tension is the same at both ends of the rope, why would the person need to travel the whole 15m? the other skater can't be stationary?