Hi guys, I am solving some magnetism questions,but somewhat confused about right hand rule. Determine the magnitude and direction of the force on an electron traveling 8.75 * 10^5 m/s horizontally to the east in vertically upward magnetic field of strnegth 0.75T? We know since this is perpindcular to the magnetic field it will have maximum since sin(90) would be 1,so we can calculate the the force easily. F = qVBsin; F = 1.05; What I don't understand is the direction first I did normally right hand rule,but since that charge is an electron it should be the opposite to what right hand rule gives us. So I got the direction as South,but my book says west that should be the direction on a given proton not electron right ?