Force on a hinge when a rod is being released

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Homework Help Overview

The discussion revolves around a uniform rod of weight W that is free to rotate about a hinge fixed to a wall. The problem involves determining the force exerted on the hinge just after the rod is released from a horizontal position.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the forces acting on the rod, including its weight and the reaction forces from the hinge and wall. There are questions about the role of the hinge being fixed and the dynamics involved just after release.

Discussion Status

Participants are actively engaging with the problem, with some providing hints and prompting for further clarification. There is recognition of the need to analyze the forces and torques, and a participant acknowledges a misunderstanding regarding the initial position of the rod.

Contextual Notes

One participant noted confusion stemming from misreading the problem, initially thinking the rod was released from a vertical position instead of horizontal. This has implications for the interpretation of forces and motion involved.

randomgamernerd
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Homework Statement

: A uniform rod of weight W is free to rotate about a hinge at one end. The hinge is fixed to a wall. If the rod is released from a horizontal position, what force will it exert on the hinge just after being released?
a)W
b)W/2
c)W/3
d)W/4
choose the correct option[/B]2.The attempt at a solution: Since the rod is just released, the only force that it will exert at the hinge is its own weight which is W. So I think the answer should be W. But I'm unable to use the fact that the hinge is fixed to a wall and I think that's the reason I'm getting my answer wrong.

Please clarify my concept.
Thanks for helping.
 
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Hello.
randomgamernerd said:
Since the rod is just released, the only force that it will exert at the hinge is its own weight which is W.
You're jumping to a conclusion here that is not justified.
Draw a free body diagram and apply the appropriate dynamical laws.
 
The only forces I could identify was the weight of the rod, the reaction force from the hinge on the rod and the reaction force from the wall on the hinge...and then?I can't figure out how to proceed...I would be grateful if you could give me a bit more hint...and then I could proceed well...I'm not requesting for a solution but just a bit more hint.
 
Can you either post a figure showing your free body diagram for the rod or describe the free body diagram in words?

What equations can you set up using your free body diagram?
 
randomgamernerd said:
the reaction force from the wall on the hinge.
That is not useful. In the free body diagram for a rigid body, only include the forces which act directly on it. How the wall and hinge interact is their own affair.
 
randomgamernerd said:
The only forces I could identify was the weight of the rod, the reaction force from the hinge on the rod and the reaction force from the wall on the hinge...and then?I can't figure out how to proceed...I would be grateful if you could give me a bit more hint...and then I could proceed well...I'm not requesting for a solution but just a bit more hint.

Ok, one hint. The rod isn't static.
 
Cutter Ketch said:
Ok, one hint. The rod isn't static.

okay...you mean a centrpetal force is acting...right?
 
This means N= W-F

where
N=reaction from hinge
W= weight of rod
F= Centripetal force
 
randomgamernerd said:
okay...you mean a centrpetal force is acting...right?
No. Centripetal force requires some speed. At the moment of release, there is acceleration but no speed yet.
Just write out the usual equations relating force to acceleration and/or torque to rotational acceleration. (Which looks to be the more useful here?)
 
  • #10
randomgamernerd said:
okay...you mean a centrpetal force is acting...right?

No, I mean the forces and torques don't add up to zero. What do they add up to?
 
  • #11
okay...I'm so sorry everyone...I missed out the word "horizontal"...From the very beginning I thought that the rod was released from a vertical position...Thats the reason I was so hell confused...Anyways...thanks for the hints...and making me reread the question(this time carefully)...I would be able to work it out now...
Sorry for the inconvenience and THANKS for the help...
 
  • #12
randomgamernerd said:
okay...I'm so sorry everyone...I missed out the word "horizontal"...From the very beginning I thought that the rod was released from a vertical position...Thats the reason I was so hell confused...Anyways...thanks for the hints...and making me reread the question(this time carefully)...I would be able to work it out now...
Sorry for the inconvenience and THANKS for the help...
Welcome to physics forums...did you get an answer
 
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