Force per unit length between two parallel whires of +/- X volts

Click For Summary
SUMMARY

The discussion focuses on calculating the force per unit length between two parallel wires charged with a current density L and separated by a distance D. The magnetic field B is defined by the equation B = μ0*I /(2πr), while the force is given by F = B × IL. Participants emphasize the importance of correctly identifying current density as J to avoid confusion and suggest deriving the expression for current in the wires to facilitate the calculation of force per unit length.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically the concepts of magnetic fields and forces.
  • Familiarity with the equations B = μ0*I /(2πr) and F = B × IL.
  • Knowledge of current density and its representation as J.
  • Basic principles of parallel circuit configurations.
NEXT STEPS
  • Research the derivation of the current in parallel wires under varying potentials.
  • Explore the implications of current density in electromagnetic force calculations.
  • Study the effects of wire separation on the magnetic field and force interactions.
  • Learn about the applications of these principles in real-world electrical engineering scenarios.
USEFUL FOR

Students studying electromagnetism, electrical engineers, and anyone interested in the principles of force interactions between charged conductors.

kryzlof
Messages
3
Reaction score
0

Homework Statement


Two parallel whires, separated by a distance D (midpoint distance), are charged with a current density L (each whire has a radius R). If the whires have the potential +/- X Volts, what is the force per unit length between them?

Homework Equations


B = μ0*I /(2πr) is describing the magnetic field at a distance r perpendicular from the whire.

F=B×IL is describing the force


The Attempt at a Solution


?
 
Physics news on Phys.org
The L in your second equation is the length of the wire, I think. Current density is the current per unit cross sectional area of the wire. It might be helpful to call this J or something so that you don't get confused.

It seems like a good idea would be to start off by getting an expression for the current in the wires. Your second equation can be rearranged to give the force per unit length in terms of the other quantities in the question.
 

Similar threads

Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
15K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
12K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K