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## Homework Statement

A block of mass

*m*slides on a rough horizontal surface from point A to point B. A force (magnitude P = 2.0 N) acts on the block between A and B. P acts on the block at 40 degrees above the horizontal. Points A and B are 1.5 meters apart. If the kinetic energies of the block at A and B are 5.0 J and 4.0 J, respectively.

a) How much work is done on the block

**as it moves from A to B**

*by the force P*b) How much work is done on the block

**as the block moves from A to B**

*by the force of friction*c) If the coefficient of kinetic friction is 0.7, what is the mass

*m*?

## Homework Equations

kinetic energy = 0.5 * m * v

^{2}

horizontal force on the block = cos(40 degrees) * 2.0 N

## The Attempt at a Solution

Well, I reasoned that the net change in kinetic energy is -1.0 J from A to B. We divide that by the change in distance so the net force acting on the block from A to B is -1.0/1.5 Newtons. Part of that is due to friction ([tex]\mu[/tex]*(mg + vertical component of P)) and part of it is due to the horizontal component of P. Obviously, since the kinetic energy is decreasing, the force due to friction is greater than the horizontal component of P.

The net force on the block is the sum of the two horizontal force vectors. I just don't know how to split them up and get parts a) and b)

edit: formatting

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