I am building a tank to produce waves.
I have two options to power the flap that will be produced to create the waves:
1. Pneumatic system
2. Motor and Cam system
Before I can order motors or pneumatic air cylinders I need to know what force will be required to move the flap the required distance to produce the waves.
Sketches of both systems are attached
Sketch of problem is attached
Fxd = mgh
P= FxA ?
The Attempt at a Solution
From attached images:
Mass of Water = 7500kg
d = tan 18 x 1 = 32.5cm
Finding mass of displaced water:
d x h x w = .325 x 1 x .75 = 243.75kg
but we are dealing with triangle so
mass of displaced water =243.75/2 = 121.875kg of water displaced
Calculating Height of water when flap is extended:
Mass of water = length of tank x width of tank x height of tank
7.5 = (10-.1625) x .75 x h
h = 1.0165 cm
d = 32.5/2 = 16.25 (as we are dealing with triangle not rectangle)
F x 16.25 = 7500x9.81x1.0165
F = 4602.4kN
Very sure I am missing something fundamental with this solution but not sure what!!
I feel I have ignored the fact that the force is being applied at 1.25m not 1m but dont know how to incorporate this.
Im also unsure if I have used the wrong figures for my Fxd=mgh solution.
I feel P=F/A can be incorporated but not sure how?
Thanks for any feedback!
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