smr101
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I've worked out (i), having problems with (ii). I know that the torque will be force x 0.75 but I haven't had any success in working out the force in the first place.
The discussion focuses on calculating the force required to accelerate a wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration, specifically addressing the torque calculations involved. The formula for force, F = ma, was applied, yielding a force of 787.2 N for acceleration. Additionally, the force required to move the wagon up a 10° incline was calculated using Fw = mgsin(angle), resulting in 3270.7 N. The participant clarified that torque calculations for the motor would use similar principles but with different values.
PREREQUISITESPhysics students, mechanical engineers, and anyone involved in calculating forces and torques in mechanical systems will benefit from this discussion.
Bystander said:What's the force required to accelerate the wagon if there's no incline?
From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ..."smr101 said:Without an acceleration, I'm not sure.
Bystander said:From the problem statement, "... accelerate the wagon from rest to 2.6 m/s over a distance of 8.2 m at constant acceleration ..."
No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.smr101 said:when there is no incline?
Bystander said:No. You've got the force to do the acceleration? Can you calculate the force necessary to move the wagon up the incline? Add them.
Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?smr101 said:= 1920 x 9.81 x sin10
= -10246.7
Bystander said:Don't just punch numbers into a calculator and blindly accept the number that comes out. What's the sin of 10°?
Bystander said:Better.