Force that will be created on the component

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SUMMARY

A mass of 22 kg dropped from a height of 180 mm impacts a component with a final velocity of 3.53 m/s. The force exerted on the component can be calculated using Newton's second law, F = m * a, where 'm' is the mass and 'a' is the acceleration. The force exerted by the mass on the component is equal to the force the component exerts back, adhering to Newton's third law of motion. The duration of the force can be determined through further calculations involving the impact time, which requires additional data on the deformation characteristics of the component.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of force calculations (F = m * a)
  • Familiarity with kinematic equations
  • Concept of impulse and momentum
NEXT STEPS
  • Calculate the impact force using F = m * a with specific acceleration values
  • Research the concept of impulse to determine the duration of force application
  • Explore material properties to assess deformation during impact
  • Learn about energy transfer during collisions and its implications on force
USEFUL FOR

Mechanical engineers, physics students, and anyone involved in impact analysis or component design.

chandran
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a mass of 22 kg is dropped vertically from 180mm on a component. I know the final velocity while the hit takes place is 3.53m/sqsec. What is
the force that will be created on the component and to what duration the force lasts.
 
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How much force does the mass exert on the componant? Wouldn't the force the componant exerted be equal and opposite, because its pushing back on the mass, to the magnitude of the force the componant exerts? As far as calculating the time I don't know.
 

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