(Force x Distance) Magnitude of velocity help

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SUMMARY

The discussion focuses on calculating the magnitude of velocity for a 2 kg mass subjected to varying forces along a distance of 7.4 meters. The force increases to 4 Newtons after 3 meters, remains constant for 2 meters, and then decreases to 0 Newtons after 7 meters. The final calculated velocity is 4.2 m/s, derived from the work-energy principle using the equation 1/2 MV^2. Participants emphasize the importance of calculating work done over each distance segment to accurately determine the velocity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the work-energy principle
  • Knowledge of basic calculus for force-distance relationships
  • Proficiency in using the equation 1/2 MV^2 for kinetic energy calculations
NEXT STEPS
  • Calculate work done using force-distance graphs
  • Explore the concept of variable force in physics
  • Learn about integration techniques for calculating work
  • Study the implications of mass and force on velocity in dynamic systems
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the relationship between force, distance, and velocity in motion scenarios.

Barukun
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Homework Statement


A 2KG mass has been graphed to increase in force after 3 meters east to 4 Newtons. it maintains 4 Newtons for 2 more meters east and then decreases back to 0 after 7 meters
..._
_/..\__...__ shape graph. I am trying to find out its magnitude of velocity at 7.4 Meters.
...^.|_|

Around about where the arrow is. (ignore the . they are just placeholders to try and show the graph shape)

Homework Equations



1/2 MV^2

The Attempt at a Solution



I already know the answer, i am trying to do the workings out. It equals 4.2 M/s
 
Physics news on Phys.org
You've got forces and distances that they are applied. Looks like you should be able to calculate the work done for each distance segment. You'll have to concoct suitable expressions for the force with respect to distance for the segments where the force is changing.
 

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