Forced Normal mode frequencies of 4 horizontal springs, 3 masses

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SUMMARY

The discussion focuses on calculating the normal mode frequencies of a system comprising three equal masses connected by four springs with a spring constant k. The key equations involved include the force equation F=m\ddot{x}, the spring potential V = 0.5kx², and the natural frequency formula ω₀² = k/m. The participants confirm that the system should yield three normal mode frequencies, and a miscalculation in the determinant expansion is identified as the reason for missing the third frequency solution.

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  • Familiarity with spring dynamics and Hooke's Law.
  • Knowledge of matrix determinants and eigenvalue problems.
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Homework Statement


Hey guys.
The title says it all pretty much. We need to find the normal mode frequencies of a driven/forced system containing 3 equal masses connected by 4 springs of equal spring constant k.

Homework Equations


F=m\ddot{x}
Spring potential
V = 0.5kx^{2}
Force-potential relationship
F = -\frac{dV}{dx}
Natural frequency of the system
ω_{0}^{2} = \frac{k}{m}

The Attempt at a Solution


So, I'm gona type this up in word and show you guys what I've done. Obviously there are 3 masses, so we expect 3 normal mode frequencies. I've found two, I don't know how to get the third one.
https://imageshack.us/scaled/large/818/normalmodefrequencyques.jpg
Thanks again guys.
 

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I haven't checked all the steps in detail. But, after you expanded your determinant, it looks like you have an overall factor of ##(2\omega_0^2-\omega^2)##. You then divided out this overall factor. I think that's where you lost your 3rd solution.
 
Yea, you're right...that's it. Thanks a lot man :)
 

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