Forces at Work: Solving for the Magnitude of Resistance

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Homework Help Overview

The problem involves calculating the magnitude of the force exerted by an apple on an arrow as it passes through. The scenario includes an arrow with a specified mass and initial and final velocities as it travels through the apple, which has a given length.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of kinematic equations to find acceleration and subsequently force. There are questions about unit conversions, particularly regarding mass and distance.

Discussion Status

Some participants have confirmed the calculation method but are exploring unit conversion issues. There is an ongoing dialogue about the correct interpretation of the problem's parameters, including the size of the apple and the mass of the arrow.

Contextual Notes

Participants note the importance of converting mass to kilograms and the apple's length to meters for accurate calculations. There is a recognition that these conversions may affect the final results.

lim
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Homework Statement



A 21.7 g arrow is shot through a 9.6 cm apple. If the arrow enters the apple at 38.5 m/s and emerges witha speed of 31.2 m/s in the same direction, what is the magnitude of the force with which the apple has resisted the arrow?

Homework Equations


vf^2 = vi^2 +2adeltax
f= ma

The Attempt at a Solution



31.2^2 = 38.5^2 +2(9.6)a
973.44 = 1482.25 + 19.2a
a = -26.5
ma=|-575|
f= 575 N
 
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lim said:

Homework Statement



A 21.7 g arrow is shot through a 9.6 cm apple. If the arrow enters the apple at 38.5 m/s and emerges witha speed of 31.2 m/s in the same direction, what is the magnitude of the force with which the apple has resisted the arrow?

Homework Equations


vf^2 = vi^2 +2adeltax
f= ma

The Attempt at a Solution



31.2^2 = 38.5^2 +2(9.6)a
973.44 = 1482.25 + 19.2a
a = -26.5
ma=|-575|
f= 575 N

Your method of calculation is correct. However, you need to watch out for the units. Convert them into proper units.
 
So mass should be in kg, so .0217(-26.5) = |-0.575| = 0.575 N, but it still said it was wrong. Am I forgetting something else?
 
lim said:
So mass should be in kg, so .0217(-26.5) = |-0.575| = 0.575 N, but it still said it was wrong. Am I forgetting something else?

Yes. The size of the apple. Convert that into m.
 
Oh! 57.51 N. Thanks for your help l46kok.
 

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