1. The problem statement, all variables and given/known data A skier on a slope inclined at 4.7 degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7 m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to rest. 2. Relevant equations uK= 0.11 v initial= 2.7 m/s v final= 0.0 m/s Fk = uK*Fnormal F=ma (v final)^2 = (v initial)^2 +2*a*d 3. The attempt at a solution (Refer to system diagram for notations and stuff!) So from what I can tell, the applied force is the horizontal component of gravity, Fgx, and the normal force is the vertical component of gravity, Fgy. The horizontal component of gravity is: Fgx= (sin4.7)(9.8)(m) The force of kinetic friction would come out to be: Fk=uK*Fgy Fk=(0.11)(cos4.7)(9.8)(m) The net force would be: Fnet = Fapplied - Fkinetic Fnet = Fgx - Fk Fgx - Fk = m*a So, solving, I get: (sin4.7)(9.8)(m) - (0.11)(cos4.7)(9.8)(m) = m*a a = 8.67 m/s^2 Now I can use acceleration to find the distance traveled by the skier: (v final)^2 = (v initial)^2 +2*a*d 0 = (2.7)^2 +(2)(8.67)(d) d= 0.42 m The actual answer is 13m and I'm sure I've done something wrong . Can someone guide me through this, please?