Skier traveling uphill with and without friction

[Bystander]

Then the total force decelerating the skier is ... ?

 

[m_eghan]

Then the total force decelerating the skier is ... ?

mg*cos30 + mg*sin30 ??!??

 

[Bystander]

You forgot the coefficient of friction.

 

[m_eghan]

You forgot the coefficient of friction.

OHHH!
μ*mg*sin30 + mg*cos30

 

[Bystander]

Close. Frictional force is the product of coefficient of friction and the normal force. One more time.

 

[m_eghan]

Close. Frictional force is the product of coefficient of friction and the normal force. One more time.

okay so if Ff = μ*Fn then...
μ*mg*cos30 + mg*sin30

 

[Bystander]

Correct. And you've done the d = (1/2)at² game for the other part of the problem once already, so you should be in business. "Windoze" insists it's going to update, so I'll be off for the next half hour.

 

[m_eghan]

Correct. And you've done the d = (1/2)at² game for the other part of the problem once already, so you should be in business. "Windoze" insists it's going to update, so I'll be off for the next half hour.

thank you so much! you have no idea how much that helped me