The discussion focuses on calculating the distance a skier travels uphill when factoring in a coefficient of kinetic friction of 0.11 on a 30-degree slope. The initial speed of the skier is 31.9 m/s, and the forces acting on the skier include friction and gravity. The correct approach involves using the equations of motion and understanding the components of gravitational force acting parallel and perpendicular to the slope. The final calculated distance is approximately 87.13 meters.
PREREQUISITESStudents studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to enhance their understanding of forces on inclined planes.
mg*cos30 + mg*sin30 ??!??Bystander said:Then the total force decelerating the skier is ... ?
OHHH!Bystander said:You forgot the coefficient of friction.
okay so if Ff = μ*Fn then...Bystander said:Close. Frictional force is the product of coefficient of friction and the normal force. One more time.
thank you so much! you have no idea how much that helped meBystander said:Correct. And you've done the d = (1/2)at2 game for the other part of the problem once already, so you should be in business. "Windoze" insists it's going to update, so I'll be off for the next half hour.