- #1

m_eghan

- 19

- 0

## Homework Statement

If the coefficient of kinetic friction in the previous problem was actually 0.11 and the slope 30 degrees, to the nearest meter how far up the hill does he go?

**the problem prior was: A skier traveling at 31.9 m/s encounters a 12 degree slope. If you could ignore friction, to the nearest meter, how far up the hill does he go? (my answer was 250m up the hill)**

## Homework Equations

Sum of the forces in the y-axis = Fn - Fgy = 0

Sum of the forces in the x-axis = Ff + Fgx = ma

## The Attempt at a Solution

I figured acceleration = Fnet / mtotal

therefore, acceleration = ((.14*mg*cos30)+(mgsin30)) / m

then the m's would cancel and it would just be..

a = (.14*g*cos30)+(gsin20)