- #1
llhalsey
- 3
- 0
Forces on a weight stack with the position of the pulleys so the weight is pulled up and the puller is moving a horizontally. Is it correct to use F=MG?
Click For Summary
SUMMARY
The discussion centers on the application of the formula F=MG in the context of a weight stack being pulled horizontally using a pulley system. Participants confirm that the force on the horizontal rope must support the weight of the object, validating the use of F=MG. Additionally, they highlight that when the weight is moved vertically, the pulley system's mechanics must be considered for accurate calculations of work and power. The complexity arises from the need to account for the distance the rope is pulled relative to the weight's movement.
PREREQUISITES- Understanding of Newton's Second Law (F=MG)
- Basic principles of pulley systems
- Knowledge of work and power calculations
- Familiarity with vector forces in physics
- Study the mechanics of pulley systems in detail
- Learn about calculating work done in mechanical systems
- Explore the relationship between force, distance, and power in physics
- Investigate real-world applications of F=MG in engineering contexts
This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the dynamics of pulley systems and force calculations in practical applications.
- #2
berkeman
Admin
- 69,346
- 24,678
llhalsey said:
Without a diagram it's hard to say for sure, but if I'm picturing it correctly, I think the answer is yes.
- #3
- #4
berkeman
Admin
- 69,346
- 24,678
llhalsey said:
The force on the horizontal rope has to support the weight of the object, so your assumption is correct. However, if you start moving the weight up or down, the pulley system has to factor into any other calculations (work, etc.).
BTW, I've moved this thread to the Homework Help forums, where all schoolwork-type questions should be posted.
- #5
HallsofIvy
Science Advisor
Homework Helper
- 42,895
- 983
I note that there are two lines from the weight to the pulley. That means that you will have to pull the rope on the left twice the distance you lift the weight.
- #6
llhalsey
- 3
- 0
SO to calculate work = FD is it as simple as the distance the rope is pulled * mass of the wt *g. and Power would be divided by the time it takes to pull the distance or is there something specific with a pulley system that needs to be take into account?
Similar threads
- · Replies 2 ·
- · Replies 6 ·
- · Replies 15 ·
- · Replies 29 ·
- · Replies 24 ·
- · Replies 11 ·
- · Replies 5 ·