zhen Messages 48 Reaction score 0 Thread starter Dec 1, 2005 #1 The question is: Attachments 001.JPG 10.5 KB · Views: 470
Pengwuino Gold Member Messages 5,112 Reaction score 20 Dec 1, 2005 #2 https://www.physicsforums.com/showthread.php?t=94383 Please read the FAQ, you must show your work, we do not do your homework for you.
https://www.physicsforums.com/showthread.php?t=94383 Please read the FAQ, you must show your work, we do not do your homework for you.
zhen Messages 48 Reaction score 0 Dec 1, 2005 #3 http://ca.geocities.com/markxiao2002/001.JPG I just forget to show the work when I upload the attachment... I just know A = V' ...so V = (A^2)/2 + C... but what should I do for the Vo? I really have no clue...can you guys give some hints? Last edited by a moderator: May 2, 2017
http://ca.geocities.com/markxiao2002/001.JPG I just forget to show the work when I upload the attachment... I just know A = V' ...so V = (A^2)/2 + C... but what should I do for the Vo? I really have no clue...can you guys give some hints?
Doc Al Mentor Messages 45,589 Reaction score 2,473 Dec 1, 2005 #4 Start with the acceleration. Integrate twice.
zhen Messages 48 Reaction score 0 Dec 1, 2005 #5 just integrate the acceleration twice...? I tryied aleady...but it makes no sense... I don't get it...
just integrate the acceleration twice...? I tryied aleady...but it makes no sense... I don't get it...
Doc Al Mentor Messages 45,589 Reaction score 2,473 Dec 1, 2005 #6 Show what you did. Since [itex]a = dv/dt[/itex], integrating a with respect to t will give you the velocity. That's step one.
Show what you did. Since [itex]a = dv/dt[/itex], integrating a with respect to t will give you the velocity. That's step one.
zhen Messages 48 Reaction score 0 Dec 1, 2005 #7 yes, I know that... but there is no function of the accelration respect to time given...
zhen Messages 48 Reaction score 0 Dec 1, 2005 #8 and the acceleration is constant in this question... I think there must be related to the word "constant"... and I still thinking...
and the acceleration is constant in this question... I think there must be related to the word "constant"... and I still thinking...