Formula for Circular Motion and Tangential Speed

[vwillis]

Homework Statement

The Earth rotates on its own axis once per day (24.0 hr). What is the tangential speed of the summit of a mountain (elevation 6409 m above sea level), which is located approximately on the equator, due to the rotation of the Earth? Take the equatorial radius of Earth to be 6379 km

I'm looking for the formula to help solve this problem

 

[Uku]

This is a very straightforward problem. You could use dimensional analysis to solve it in your head.

$$v=\omega R$$

You do the rest!

 

[vwillis]

I used that formula it didnt accept my answer.
v=WR
W=2pi/T
W=2pi/86400s

V=.000074*63979
.463894
I won't accept that onwebassign.net

 

[Uku]

Where did you get that weird radius from?

63979

 

[vwillis]

i meant to say 6379

 

[Uku]

Look at your data again, the radius is still weird.

 

[vwillis]

Its correct i just don't know what to do

 

[Uku]

Why are you given two radiuses then?

Good night!

 

[vwillis]

nvrminf thanks so much.. i forgot to change the radius to m