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Formula for electric potential energy

  1. Apr 20, 2014 #1
    In a velocity selector apparatus, i had an electric potential set across two points, and a proton at rest at one end. The potential was 350 V.

    My instructor used :

    qV = 1/2 mv^2 to find the velocity at the end of the apparatus.

    Where did the left hand side of the eqn come from??
     
  2. jcsd
  3. Apr 20, 2014 #2

    Doc Al

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    Staff: Mentor

    That describes the energy gained by a charge q moving through a potential difference V. (The work done by the field on the charge.)
     
  4. Apr 20, 2014 #3

    Doc Al

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    Staff: Mentor

  5. Apr 20, 2014 #4
    qv=(0.5)mv^2
    This expression indicates Kinetic Energy gained by a body with charge q while moving in a region of Electric potential v.
     
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