Formula for finding logarithms possible?

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A formula for calculating logarithms of any base exists, expressed as log_k(x) = log_n(x) / log_n(k), where k and n are any positive numbers greater than 1. While this formula allows for conversions between bases, practical calculations often rely on logarithmic tables, slide rules, or calculators. Logarithms are transcendental functions, and methods like Taylor series or Newton-Raphson can approximate their values, though these are not practical for manual calculations. Although it is theoretically possible to derive logarithmic values without a calculator, the methods are complex and not commonly used. Ultimately, while formulas exist, they are often impractical for everyday use.
Thymo
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Is it possible to make a formula for logarithms of any base?

logb(a)=x

I want to find x through some formula. I've seen that you can use a series for e as the base, is that the only base that can be solved for?

Is there any work being done to accomplish this, or, maybe it has been proven impossible? In that case, how was it proven impossible?

Sorry if this is a noobish question... In my defence, a noob can't recognize a noobish question...

Thanks in advance for any answers.
~ Thymo
 
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Sure it's possible. If you know one base, you know all bases.

The equation you are looking for, is: \log_k x=\frac{\log_n x}{\log_n k} where k and n can be any positive number above 1. (Do you see why this formula works?)

So if you use e as your end base, you have a fraction bewteen two logarithms which equals to x.
 
Last edited:
I don't suppose you're looking for the change of base formula, used when a calculator only has a log10( ) key:

logb(a) = log10(a)/log10(b)

Actually you don't have to use base 10; anything, including e, is workable. (Of course, you can't use 1, 0, negative numbers, etc.)

If this looks new I think I can derive it, free of charge.


Everyone is a rehabilitated noob.
 
But this doesn't really help me do logs without a calculator does it? ... :confused:
 
Thymo said:
But this doesn't really help me do logs without a calculator does it? ... :confused:

If you want to do it by hand you should use a table/slide rule. Failing those you're going to have to use Newton's method or something similar.
 
Thymo said:
Is there any work being done to accomplish this, or, maybe it has been proven impossible? In that case, how was it proven impossible?

The logarithm is a transcendental function. The only way to reduce it to something like a polynomial with rational coefficients is through infinite series like Taylor's or iterative processes like Newton-Raphson. However, practical applications use either logarithmic tables/slide rules or calculating machines.
 
slider142 said:
The logarithm is a transcendental function. The only way to reduce it to something like a polynomial with rational coefficients is through infinite series like Taylor's or iterative processes like Newton-Raphson. However, practical applications use either logarithmic tables/slide rules or calculating machines.



So it's possible to use either a Taylor Series or "Newton-Raphson"-method(??). There EXISTS a formula that makes it possible, but impractical? Does it EXIST? Any LINKS or EXPLENATIONS? :blushing:
 
Thanks! It seems as if I have a lot to work with... At least it's something... ;)
 
  • #10
Thymo said:
There EXISTS a formula that makes it possible, but impractical?

You already know it's possible, if you accept that a calculator can do it. You could simply make a circuit diagram of the calculator and trace through its operation when given the appropriate set of keystrokes. That's far less practical, but possible.
 
  • #11
CRGreathouse said:
You already know it's possible, if you accept that a calculator can do it. You could simply make a circuit diagram of the calculator and trace through its operation when given the appropriate set of keystrokes. That's far less practical, but possible.

That might not necessarily mean a formula exists. The calculator could just be estimating values for the exponential and then by much trial and error, give a 10 decimal value display :-p
 

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