Formula for the magnetic field inside a solenoid

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SUMMARY

The magnetic field inside a solenoid can be computed using the formula B = μ₀ni, where B is the magnetic field, μ₀ is the permeability of free space (1.25664 x 10^(-6) N/A²), n is the number of turns per unit length, and i is the current in amperes. For a solenoid with 390 turns, a length of 13.1 cm, and a current of 29.8 mA, the magnetic field can be calculated by first determining n and then applying the formula. The assumption of an infinitely long solenoid simplifies the calculation, ensuring that the magnetic field remains constant throughout the interior.

PREREQUISITES
  • Understanding of electromagnetic theory
  • Familiarity with solenoid properties
  • Knowledge of the permeability of free space
  • Basic algebra for manipulating equations
NEXT STEPS
  • Learn about the derivation of the solenoid magnetic field formula
  • Explore the concept of magnetic field lines in solenoids
  • Study the effects of solenoid length on magnetic field uniformity
  • Investigate applications of solenoids in electromagnetic devices
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Physics students, electrical engineers, and anyone interested in understanding the principles of electromagnetism and solenoid applications.

ashleyd
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A 29.8 mA current is carried by a uniformly wound air-core solenoid with 390 turns. the length of the coil is 13.1 cm, with a diameter of 20.8mm. The permeability of free space is 1.25664 X 10^(-6) N/A^2
compute the magnetic field inside the solenoid. answer in units of T

Relevant equations:
None

The attempt at a solution
no attempt, am stuck at what formula should be used
 
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you need formula ?

its B = μoni :smile:
 
integral(B dot dl) = Ithrough*mu0

Assume the solenoid is infinitely long. Well, if that is the case, then B inside the solenoid is constant. Anyways, If you draw two infinitely long rectangles, then you will get the formula posted above.
 

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