Compute Sin Coeffs for f(x)=e^(-x^2) on [0,2π]

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SUMMARY

The discussion centers on computing the sine coefficients for the function f(x) = e^(-x^2) over the interval [0, 2π]. Participants clarify that while f(x) is defined on [0, 2π], it is not inherently periodic, as the Gaussian function is not periodic. The correct approach involves using the half-range sine expansion, but it is essential to determine the appropriate periodic extension, particularly the odd periodic extension, to accurately compute the coefficients. The Fourier series (FS) will converge to e^(-x^2) only on the interval (0, π), and outside this range, it represents the odd 2π periodic extension.

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Compute the sine coefficients for f(x)=e^{-x^{2}} on the interval [0,2\pi]. Does this mean f(x+2\pi k)=f(x), k\in\mathbb{Z}? Can x\in[0,\infty)?
 
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glebovg said:
Compute the sine coefficients for f(x)=e^{-x^{2}} on the interval [0,2\pi]. Does this mean f(x+2\pi k)=f(x), k\in\mathbb{Z}? Can x\in[0,\infty)?

You have to know what periodic function you are expanding in a FS before you can calculate the Fourier coefficients. Do you mean to calculate the coefficients for the odd periodic extension of ##f(x)##? Do you know what the graph of the odd periodic extension would look like? Does that answer your last question?
 
It says on the interval [0,2\pi]. Does this mean f(x+2\pi k)=f(x), k\in\mathbb{Z}?

A Fourier series is an expansion of a periodic function in terms of an infinite sum of sines and cosines. A real-valued function f(x) of a real variable is called periodic of period T>0 if f(x+T) = f(x) for all x\in\mathbb{R}.

So, can x\in[0,\infty)?
 
glebovg said:
It says on the interval [0,2\pi]. Does this mean f(x+2\pi k)=f(x), k\in\mathbb{Z}?

A Fourier series is an expansion of a periodic function in terms of an infinite sum of sines and cosines. A real-valued function f(x) of a real variable is called periodic of period T>0 if f(x+T) = f(x) for all x\in\mathbb{R}.

So, can x\in[0,\infty)?

I think you have answered your own question. Of course if a function is defined on ##[0,2\pi]## and periodic with period ##2\pi## it is defined for all x. But if you want to calculate the coefficients for your f(x) you need to know what periodic extension you are using. That's why I asked you if you mean to use the odd periodic extension of ##e^{-x^2}## to calculate the coefficients.
 
I need to use the the half-range sine expansion. Correct?
 
LCKurtz said:
I think you have answered your own question. Of course if a function is defined on ##[0,2\pi]## and periodic with period ##2\pi## it is defined for all x. But if you want to calculate the coefficients for your f(x) you need to know what periodic extension you are using. That's why I asked you if you mean to use the odd periodic extension of ##e^{-x^2}## to calculate the coefficients.

I need to use the the half-range sine expansion. Correct? However, the problem does not state that the function is periodic, nor that it is defined on [0,2\pi]. After all, the Gaussian function is not periodic. My instructor said that I should only consider [0,\infty), but then this would not satisfy the definition of a periodic function.
 
glebovg said:
I need to use the the half-range sine expansion. Correct? However, the problem does not state that the function is periodic, nor that it is defined on [0,2\pi]. After all, the Gaussian function is not periodic. My instructor said that I should only consider [0,\infty), but then this would not satisfy the definition of a periodic function.

That's right. But if you are going to find a FS that represents ##e^{-x^2}## on some interval, you must decide what interval. You must know that to use the appropriate half range formulas. I would suggest you ask your instructor what interval he wants. It can't be ##(0,\infty)## unless you are talking about a Fourier transform, not a FS.
 
In this case T=\pi, but he said that I should work on the positive x-axis only. That's what bothers me. You can't do that, right? f(x) would not be periodic and it would not work because a Fourier series is an expansion of a periodic function in terms of an infinite sum of sines and cosines.
 
glebovg said:
In this case T=\pi, but he said that I should work on the positive x-axis only. That's what bothers me. You can't do that, right? f(x) would not be periodic and it would not work because a Fourier series is an expansion of a periodic function in terms of an infinite sum of sines and cosines.

That's right. It isn't going to work on the positive x axis. The half range sine series will only converge to ##e^{-x^2}## on ##(0,\pi)##. What the FS will converge to outside of that interval is the odd ##2\pi## periodic extension of ##e^{-x^2}##, except for multiples of ##\pi##. Your teacher may be referring to the fact that the formula for the coefficients only uses positive values of ##x##.
 

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