Fourier Transform of a sinc like equation

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InquiringM1nd
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I have been given this [tex]y(t)=\frac{sin(200πt)}{πt}[/tex]

All I want is to find, is how the rectangular pulse will look like if I take the transformation of the above. That "200" kind of confusing me, because it isn't a simple [tex]sinc(t)=\frac{sin(πt)}{πt}[/tex]

I need somehow to find the height of the pulse and frequency range.

If I had Y(f) after the Transformation, could I just use Fourier theorem below

[tex]y(0) = \int_{-\infty}^\infty Y(f)\,\mathrm df[/tex]

to find the rectangle area? But also, I don't understand, at y(0) , it is supposed to be the whole area of the pulse or just the area at the center of the rectangle?
 
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I'm honestly not well versed in Fourier transforms, so I'm afraid I can't quite help you there. But isn't y(t) basically...

[tex]y(t) = \frac{sin(200\pi t)}{\pi t} = 200 \frac{sin(200 \pi t)}{200 \pi t} = 200 sinc(200t)[/tex]

I don't suppose you could utilize that?
 
Char. Limit said:
I'm honestly not well versed in Fourier transforms, so I'm afraid I can't quite help you there. But isn't y(t) basically...

[tex]y(t) = \frac{sin(200\pi t)}{\pi t} = 200 \frac{sin(200 \pi t)}{200 \pi t} = 200 sinc(200t)[/tex]

I don't suppose you could utilize that?

oh lol, I am tired a lot, I guess -.-

Thanks.