Fourier transform of x(t)=u(t)-u(t-1)

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SUMMARY

The Fourier transform of the function x(t) = u(t) - u(t-1) is derived using the properties of the Fourier transform. The transform of u(t) is πδ(ω) + 1/jω, while the transform of u(t-1) incorporates the time-shifting property, resulting in the expression πδ(ω) + e^{-jω}/(jω). This establishes the complete Fourier transform for the given function.

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mugzieee
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Im trying to get the Fourier transform of x(t)=u(t)-u(t-1)
from what i know the FT of u(t) is pi*delta(omega)+1/jw
so for the u(t-1) would we have to use the time shifting property of Fourier transforms so that it becomes pi*delta(omega)+1/jw*(exp(-jw_o)??
 
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A small correction:
[\pi\delta(w) + 1/(jw)] e^{-jw} = \pi\delta(w) + e^{-jw}/(jw)
 

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