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Fourier transform of x(t)=u(t)-u(t-1)

  1. Aug 8, 2006 #1
    Im trying to get the fourier transform of x(t)=u(t)-u(t-1)
    from what i know the FT of u(t) is pi*delta(omega)+1/jw
    so for the u(t-1) would we have to use the time shifting property of fourier transforms so that it becomes pi*delta(omega)+1/jw*(exp(-jw_o)??
  2. jcsd
  3. Aug 9, 2006 #2
    A small correction:
    [TEX][\pi\delta(w) + 1/(jw)] e^{-jw} = \pi\delta(w) + e^{-jw}/(jw)[/TEX]
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