Fourier transform of x(t)=u(t)-u(t-1)

1. Aug 8, 2006

mugzieee

Im trying to get the fourier transform of x(t)=u(t)-u(t-1)
from what i know the FT of u(t) is pi*delta(omega)+1/jw
so for the u(t-1) would we have to use the time shifting property of fourier transforms so that it becomes pi*delta(omega)+1/jw*(exp(-jw_o)??

2. Aug 9, 2006

doodle

A small correction:
[TEX][\pi\delta(w) + 1/(jw)] e^{-jw} = \pi\delta(w) + e^{-jw}/(jw)[/TEX]