Fourier Transforming a HgTe 2D Hamiltonian

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SUMMARY

The discussion focuses on deriving the Fourier transform of a 2D HgTe Hamiltonian with periodic boundary conditions (PBC) in the x-direction and vanishing boundary conditions in the y-direction. The Hamiltonian is expressed in terms of Nambu spinors and Pauli matrices, with specific parameters A, M, and B. The user successfully splits the Hamiltonian into two parts, H_x and H_y, and performs the Fourier transform on H_y to obtain a real-space representation. The final Hamiltonian combines both parts, resulting in a 2D Nambu spinor representation with the correct boundary conditions applied.

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  • Knowledge of Nambu spinors and Pauli matrices
  • Experience with boundary conditions in quantum mechanics
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DeathbyGreen
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Hi! I am currently trying to derive the Fourier transform of a 2D HgTe Hamiltonian, with k_x PBC and vanishing boundary conditions in the y direction at 0 and L. Here is the Hamiltonian:

<br /> H = \sum_{k}\tilde{c_k}^{\dagger}[A\sin{k_x}\sigma_x + A\sin{k_y}\sigma_y + (M-4B+2B[\cos{k_x} + \cos{k_y}])\sigma_z]\tilde{c_k}<br />

Where the \sigma_i are the Pauli matrices, and A,M, and B are material dependent parameters, and the \tilde{c_k}^{\dagger} and \tilde{c_k} are the Nambu spinors (\tilde{c_k} = (c_k,c^{\dagger}_k)) and the c's are the fermion creation/annihilation operators. So what I want to do is Fourier transform in the y direction to real space, and leave the x direction in momentum space. My attempt was to split the H into two parts,

<br /> H_x = \sum_{k_x}\tilde{c_k}^{\dagger}[A\sin{k_x}\sigma_x + (M-4B+2B[\cos{k_x})\sigma_z]\tilde{c_k}<br />

<br /> H_y = \sum_{k_y}\tilde{c_k}^{\dagger}[ A\sin{k_y}\sigma_y + (M-4B+2B[\cos{k_y}])\sigma_z]\tilde{c_k}<br />

I took the Fourier transform into real space for H_y and got this:

<br /> H_y = \sum_i^L\tilde{c_i}^{\dagger}D\tilde{c_i} + \sum_i^{L-1}(\tilde{c_{i+1}}^{\dagger}T\tilde{c_i} + \tilde{c_i}^{\dagger}T^{\dagger}\tilde{c_{i+1}})<br />

With the matrices being equal to
<br /> D = (M-4B)\sigma_z, \quad\quad T = \left(\frac{B}{a^2}\sigma_z - \frac{A}{2ia}\sigma_y\right)<br />

But now it doesn't make sense to add the two parts together...I was thinking that maybe I Fourier transform the whole thing into real space, and then write it in Nambu notation and include boundary conditions on the matrix like for y direction j and x direction i c_i = c_L+1 and c_{j-1} = 0, c_{L+1} = 0. Could someone help point me in the right direction? I've worked on 1D matrices in PBC before but I'm not sure how it should look in 2D. Would the Nambu spinors be 4N length? And if I were to FT into frequency space in the y direction, would the same solution method apply?
 
Last edited:
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I figured it out in case anyone is curious. The trick was to Fourier transform all of the c_k operators into position space, giving 2-D Nambu spinors (length 4N) of c_{i,j} and Fourier transforming the k_y into position space (the Fourier transforms lead to Delta functions, which can be rewritten as c operators). Because the k_x was PBC, I left that in momentum space, so the final product came out to

<br /> H = \sum_{i,j}^{L}\sum_{k_x}[c_{i,j}^{\dagger}Dc_{i,j} + c_{i,j}^{\dagger}(A\sin{k_x}\sigma_x + 2B\cos{k_x}\sigma_z)c_{i,j}] + \sum_i^{L-1}(c_{i,j}^{\dagger}T_ic_{i,j} + c_{i,j}T^{\dagger}c_{i,j}^{\dagger})<br />
 

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