Fraction of heat energy used to do expansion work of a gas?

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Homework Help Overview

The discussion revolves around a problem involving a monatomic ideal gas where heat energy flows into the gas, causing an increase in volume at constant pressure. Participants are examining the fraction of heat energy that is converted into expansion work.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the fraction of heat energy used for work by applying the first law of thermodynamics and substituting relevant equations. They express confusion over a discrepancy between their calculated fraction and the answer key. Other participants clarify that the original poster mistakenly calculated the ratio of internal energy change to heat instead of work to heat.

Discussion Status

Some participants have provided clarifications regarding the calculations and the correct interpretation of the question. There is ongoing exploration of the relationships between the variables involved, particularly regarding the ideal gas law and its application in the context of the problem.

Contextual Notes

Participants are discussing the implications of constant pressure and the ideal gas law, which are central to the problem's setup. There is an acknowledgment of potential confusion regarding the definitions and relationships between work, heat, and internal energy.

JustinLiang
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Homework Statement


Heat Q flows into a monatomic ideal gas, and the volume increases while the pressure is kept constant. What fraction of the heat energy is used to do the expansion work of the gas?

Homework Equations


ΔU = Q - W
Q = nC_pΔT
W = PΔV
C_p = C_v + R => C_p = 3R/2 + R => C_p = 5R/2

The Attempt at a Solution


So we sub in the Q and W in the internal energy formula and we get:
ΔU = nC_pΔT - PΔV
ΔU = (5/2)(nRΔT) - PΔV
ΔU = (5/2)(PΔV) - PΔV
ΔU = (3/2)(PΔV)

Therefore we can take ΔU/Q to find the fraction:
(3/2)(PΔV)/(5/2)(PΔV)

Which gives me 3/5. However the answer is 2/5. What am I doing wrong?
Personally, I think the answer key is wrong.

Thanks.
 
Last edited:
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I know this is an old question, but I thought I'd reply for future students that need help with this question.

All of the work shown is right, except for the very end. The question wants the ratio of W/Q, while the original poster found the ratio of ΔU/Q.

W/Q =
PΔV / (5/2)(PΔV) = 2/5
 
Could someone please explain to me how (nRΔT) = PΔV in the third step of this derivation?
 
BabyPhys said:
Could someone please explain to me how (nRΔT) = PΔV in the third step of this derivation?
Ideal gas law. PV=nRT. If P is constant, then PΔV=nRΔT

Chet
 

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