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Why specific latent heat of vaporisation > fusion?

  1. May 12, 2016 #1
    1. The problem statement, all variables and given/known data
    image.jpg

    2. Relevant equations
    First law of thermodynamics, ΔU=q+W

    3. The attempt at a solution
    Ok so, I know that when liquid evaporates, the change in volume is much greater than that when solid melts. And for both cases, distance of separation of atoms increases too, so PE increases, and hence, internal energy increases.
    So, ΔU=mL+ pΔV
    L=(ΔU-pΔV) /m
    But how do we know that the term (ΔU-pΔV) is greater for vaporisation than that of fusion?
     
  2. jcsd
  3. May 12, 2016 #2
    Well, that is in fact the main essence of the answer.

    There is a sign problem here. The work done on the system ##W## should be ## - p \Delta V## - do you see why?
     
  4. May 12, 2016 #3
    Ahh I see why now. Yup, because it's work done by system.
    Thanks !
     
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