[ Frames ] Determining the resultant forces at pins B and C

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SUMMARY

The discussion focuses on determining the resultant forces at pins B and C in a frame analysis problem. The correct answers identified are Fcd = 350 lb and Fbe = 1531.25 lb (or 1.53 kip). Participants emphasize the importance of clearly documenting calculations and suggest starting with summing moments about one of the supports to find support reactions. Additionally, the significance of recognizing two-force members in the analysis is highlighted.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with frame analysis techniques
  • Knowledge of support reactions and moment summation
  • Ability to interpret force diagrams
NEXT STEPS
  • Study the method of joints in frame analysis
  • Learn about two-force member characteristics in structural analysis
  • Explore the concept of moment summation for support reactions
  • Review examples of static equilibrium problems in engineering mechanics
USEFUL FOR

This discussion is beneficial for civil engineers, structural analysts, and students studying mechanics who are focused on frame analysis and static equilibrium problems.

student314
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So I'm a little bummed out about this one, I'd appreciate the help. Apparently the correct answers should be Fcd = 350lb, Fbe = 1531.25lb, or 1.53 kip.

Problem can be viewed here: http://i.imgur.com/pK79lVN.png

Here's my attempt at solution album: http://imgur.com/a/GQsxJ

What can I do? Did I do something wrong? Thanks
 
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There's a reason why we have the template here. There's also a reason why we say "Don't post images of your work".

That picture is extremely messy and hard to follow. I'm not even sure what you, re doing on that page.
 
I am having trouble seeing what you are doing, I am not following your numbers. It is always a good idea to see if you can determine support reactions first by summing moments about one of the supports before you break apart the individual frame members. You will be able to get the horizontal force reactions. Note that the 1050 pound load acts at the center of its distribution when determining such reactions. Also take advantage of the so called 2 force members where end reactions of these members must be equal and opposite and directed toward each other along the same line of action. You must write down your equations more clearly. Use a sharp pencil!
 

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