Free Body Diagrams: Static Equilibrium

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SUMMARY

The discussion focuses on calculating the force required to maintain static equilibrium for two frictionless blocks, A and B, each with a mass of 5 kg. The force F is determined using the equations of motion, specifically resolving forces in the x and y directions. The final calculation yields a force of 283 N, derived from the acceleration of the system and the gravitational force acting on the blocks. The angle of application for the force is specified as 20 degrees.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of Newton's laws of motion
  • Familiarity with trigonometric functions in physics
  • Ability to resolve forces into components
NEXT STEPS
  • Study the concept of static equilibrium in detail
  • Learn how to apply Newton's second law in multi-body systems
  • Explore trigonometric applications in physics problems
  • Practice solving problems involving frictionless surfaces and inclined planes
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This discussion is beneficial for physics students, educators, and anyone interested in mastering the principles of static equilibrium and force analysis in mechanics.

hunter007
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Homework Statement



Blocks A & B each have mass 5kg, and all contact surfaces are frictionless.

Determine the force F needed to keep the blocks in static equilibrium, and the forces on all contact surfaces.

1ecfa665f27769be8679c7df4a6cd8af.jpg


Homework Equations



I know I need to find where Fx= 0 and where Fy= 0.

The Attempt at a Solution



Fx = Fcos20
Fy= Fsin20 - 5 kg

Am I even close?
 
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Hi hunter007, welcome to PF.
When you apply force F to the systemis, the acceleration of the system is
a = F/(Ma + Mb)...(1). It is parallel to the ground.
Since block A is not attached to the block B, due the inertia, it will experience an equal and opposite acceleration. The block A will remain rest when component of the weight of the block A balances the component of the acceleration.
Equate these components and find a. Put this value in equation(1) to get F.
 
Could you explain a little more on how to get a? Once I find that I could find F.
 
mg*sinθ = a*cosθ.
Find a.
 
a = 5(9.8)*tan(30)
= 28.3

F= 28.3(5+5) = 283 N.

Did I do it right?
 
The given angle is 20 degrees.
 

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