Frequency and viscous friction in a spring?

[nothGing]

Hi.
may i ask the relationship(formula) between frequency and viscous friction in a spring?

 

[cragar]

are you talking about hookes law F=-Kx
And the angular frequency would be w=square root of k/m

 

[nothGing]

your equation is right if not consider the viscous friction, but since it must consider the friction, so how arh?

 

[Curl]

In a damped oscillator the resistance is just modeled as proportional to velocity. The frequency has nothing to do with the friction force, it will just increase power delivered to the liquid.

If you know spring constant and frequency, then you can find v(x) by solving the ODE. I guess that's what you're asking.

 

[PJC01]

Hello,

The relationship between frequency and viscous friction in a spring can be described by the following formula:

f = (1/2π) * √(k/m) * (1 - ζ^2)^1/2

Where:
f = frequency of the spring's oscillations
k = spring constant
m = mass attached to the spring
ζ = viscous damping coefficient

This formula shows that as the frequency of the spring's oscillations increases, the viscous friction also increases. This is because higher frequencies result in more rapid and frequent movements of the spring, causing more energy to be dissipated through friction.

Additionally, the presence of viscous friction in a spring can also affect its natural frequency, or the frequency at which it will oscillate without any external forces. Viscous friction can decrease the natural frequency of a spring, making it oscillate at a slower rate.

I hope this helps to answer your question. Let me know if you have any further inquiries.

Best,