What is the wave speed in the bridge?

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SUMMARY

The wave speed in a pedestrian bridge that resonates like a string fixed at both ends can be calculated using the formula Velocity = (frequency)(wavelength). Given a bridge length of 73.0 m and a fundamental resonance frequency of 0.600 Hz, the correct wave speed is determined by first recognizing that the fundamental resonance corresponds to half a wavelength. Therefore, the wavelength is twice the length of the bridge, resulting in a wave speed of 87.6 m/s, not the initially calculated 44 m/s.

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CMATT
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Homework Statement


A certain pedestrian bridge in England resonates like a string fixed at both ends. If the bridge is 73.0 m long and its fundamental resonance is at 0.600 Hz, what is the wave speed in the bridge?

Homework Equations


Velocity = (frequency)(wavelength)

The Attempt at a Solution



wavelength = 73.0 m
frequency = .600 Hz
velocity = find it

v = (.600)(73.0)
v = 43.4 = 44 m/s

I got this wrong on my hw, I thought this was how to do it? Could someone please show me what I am doing wrong?
Thank you for your help
 
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CMATT said:

Homework Statement


A certain pedestrian bridge in England resonates like a string fixed at both ends. If the bridge is 73.0 m long and its fundamental resonance is at 0.600 Hz, what is the wave speed in the bridge?

Homework Equations


Velocity = (frequency)(wavelength)

The Attempt at a Solution



wavelength = 73.0 m
frequency = .600 Hz
velocity = find it

v = (.600)(73.0)
v = 43.4 = 44 m/s

I got this wrong on my hw, I thought this was how to do it? Could someone please show me what I am doing wrong?
Thank you for your help
Note that the fundamental resonance is not the same thing as frequency.
 
Multiply by 2.

The "fundamental resonance" is when the bridge is resonating at only half a wavelength. To correct for this to find the velocity, multiply the length of the bridge by 2.
 

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