Frequency of sound received by an observer

Click For Summary

Homework Help Overview

The discussion revolves around the frequency of sound received by an observer when a sound source crosses a specific point (the origin). The problem involves concepts from wave mechanics, particularly the Doppler effect and the propagation of sound waves.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to apply the Doppler effect formula but questions their reasoning regarding the velocities of the source and observer. Other participants raise questions about the observer's proximity to the crossing point and the implications of sound travel time on frequency perception.

Discussion Status

Participants are exploring the implications of sound travel time and the geometry of the situation. Some guidance has been offered regarding the need for a sketch to visualize the problem, and there is acknowledgment of initial misunderstandings without reaching a consensus on the exact interpretation of the problem statement.

Contextual Notes

There is uncertainty regarding the distance between the observer and the crossing point, which may be relevant to the problem but is not explicitly stated in the problem description.

PSN03
Messages
100
Reaction score
9
Homework Statement
A source and an observer are situated on two perpendicular tracks as shown in the figure the observer is at rest and source is moving with a speed 50m/s the source emits sound waves of frequency 90Hz which travel in the medium with velocity 200m/s the frequency of sound heard by observer when the source crosses the origin is
Relevant Equations
By dopler's equation we know that
f'=f(v±vo/v±vs)
Where
f'= new frequency
vo=velocity of observer
vs=velocity of source
v=velocity of sound
My thought process was this,
They are asking us to find the frequency of sound received by observer when the source reaches at origin. According to me when the source reaches origin there would be no component of source's velocity in the direction of observer, hence vs=0
vo=0 since the observer is stationary

Therefore by the formula I should get the answer as
f'=f(v±0/v±0)
=f
Hence no change in frequency should be observed. But my answer is wrong.
Lease tell me where am I going wrong?
 

Attachments

  • download.png
    download.png
    1.8 KB · Views: 201
Physics news on Phys.org
How close is the observer to the crossing point of the tracks ?
 
PSN03 said:
Hence no change in frequency should be observed. But my answer is wrong.
Lease tell me where am I going wrong?
It takes time for the sound to travel from the source to the observer. At the instant when the source crosses the origin, the observer is hearing the sound that was emitted by the source at an earlier time (when the source was not yet at the origin). Some geometry will come into play. So, you need a good sketch of the situation.
 
  • Like
Likes   Reactions: PSN03 and etotheipi
TSny said:
It takes time for the sound to travel from the source to the observer. At the instant when the source crosses the origin, the observer is hearing the sound that was emitted by the source at an earlier time (when the source was not yet at the origin). Some geometry will come into play. So, you need a good sketch of the situation.
Yes...I got it later. Thanks for your help and I feel so stupid for forgetting such a simple point.😅
 
No need to feel stupid. My first reaction was like yours. I wonder if the actual problem statement mentions something of a distance between observer and crossing point ?
 
BvU said:
No need to feel stupid. My first reaction was like yours. I wonder if the actual problem statement mentions something of a distance between observer and crossing point ?
I guess the distance is enough for our answer to come right, though it isn't mentioned.
 

Similar threads

Replies
8
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 26 ·
Replies
26
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 22 ·
Replies
22
Views
1K
Replies
3
Views
4K
Replies
1
Views
2K