Fresnel Coefficient for Unpolarised Light

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SUMMARY

The discussion centers on calculating the Fresnel coefficient for unpolarised light, specifically for a linearly polarised plane wave incident at an angle theta. The user initially attempts to average the Fresnel coefficients for s and p-polarised light, represented as r(θi) = (rs + rp)/2 and t(θi) = 1 - r(θi). However, it is clarified that unpolarised light does not exist in this context, and a more accurate method involves summing the squares of the individual Fresnel coefficients for each polarisation component. The correct expression for the electric field vector is E = E cos(α)√{s} + E sin(α)√{p}, where α denotes the angle of alignment.

PREREQUISITES
  • Understanding of Fresnel equations for s and p-polarised light
  • Knowledge of electric field vector representation in optics
  • Familiarity with the concept of polarisation in electromagnetic waves
  • Basic mathematical skills for combining coefficients and calculating averages
NEXT STEPS
  • Study the derivation of Fresnel equations for both s and p-polarised light
  • Learn how to calculate the combined Fresnel coefficients using the power summation method
  • Explore the implications of polarisation in optical devices like cameras and films
  • Investigate the mathematical principles behind vector addition in wave optics
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Students and professionals in optics, physics, and engineering fields who are working with light polarisation and its effects on reflection and transmission in various media.

Ikaros
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Homework Statement

A homework problem asks me to find the Fresnel coefficient for a linearly polarised plane wave, which is incident under an angle theta, whose electric field vector can be given as:

E=Ecos\hat{s}+Esin\hat{p}

\hat{s} and \hat{p} are the unit vectors for s-polarised and p-polarised waves.

The attempt at a solution

The previous question on my homework sheet asked me to derive the Fresnel equations for s and p-polarised waves, which I did starting with the bondary conditions. Here, I believe I have an unpolarised wave. My initial assumption was to take the average of both s and p-polarised light that I worked out previously.

For example,

r(\thetai)=(rs+rp)/2

and

t(\thetai)=1-r(\thetai)

However, I'm concerned this is an oversimplification and a more robust approach is in order. I'd love a nudge in the right direction or a thumbs up if my initial approach looks fine.

Thanks.
 
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For your purposes (this question) unpolarized fields do not exist. You may combine the polarizations; such as what piece of film or a camera does. But there is no unpolarized light.
 
Antiphon said:
For your purposes (this question) unpolarized fields do not exist. You may combine the polarizations; such as what piece of film or a camera does. But there is no unpolarized light.
A poor choice of word by me, but I did account for the polarisation components due to the wave's orientation by averaging the Fresnel coefficients in my attempt above.

I note an error in my opening post as the wave should be E=Ecos\alpha\hat{s}+Esin\alpha\hat{p}.

The wave is alinged by \alpha with the two terms representing the relevant polarisation component projections. Therefore, the s and p-polarised components could be expressed by their own Fresnel equations - I just need to combine them. I'm just not sure how (I should have taken a Maths minor...) I'd appretiate any help.
 
Last edited:
Averaging fields in not ideal; you should combine them by summing squares (and perhaps taking the root of the sum) because the two polarizations cannot interfere but their separate powers would add.

This is what an "unpolarized detector" would measure as the reflection.
 
Antiphon said:
Averaging fields in not ideal; you should combine them by summing squares (and perhaps taking the root of the sum) because the two polarizations cannot interfere but their separate powers would add.

This is what an "unpolarized detector" would measure as the reflection.
Thanks for the tip. That looks like the way to go.
 

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